63+17x-10x^2=2x^2+16x

Solution for 63+17x-10x^2=2x^2+16x equation:

63+17x-10x^2=2x^2+16x

We move all terms to the left:

63+17x-10x^2-(2x^2+16x)=0

We get rid of parentheses

-10x^2-2x^2+17x-16x+63=0

We add all the numbers together, and all the variables

-12x^2+x+63=0

a = -12; b = 1; c = +63;
Δ = b2-4ac
Δ = 12-4·(-12)·63
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-55}{2*-12}=\frac{-56}{-24}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+55}{2*-12}=\frac{54}{-24}
=-2+1/4
$